Integrand size = 25, antiderivative size = 75 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=-\frac {3}{2} b \left (2 a^2+b^2\right ) x+\frac {6 a b^2 \cos (c+d x)}{d}+\frac {3 b^3 \cos (c+d x) \sin (c+d x)}{2 d}+\frac {\sec (c+d x) (a+b \sin (c+d x))^3}{d} \]
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Time = 0.05 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.120, Rules used = {2940, 12, 2723} \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=-\frac {3}{2} b x \left (2 a^2+b^2\right )+\frac {6 a b^2 \cos (c+d x)}{d}+\frac {\sec (c+d x) (a+b \sin (c+d x))^3}{d}+\frac {3 b^3 \sin (c+d x) \cos (c+d x)}{2 d} \]
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Rule 12
Rule 2723
Rule 2940
Rubi steps \begin{align*} \text {integral}& = \frac {\sec (c+d x) (a+b \sin (c+d x))^3}{d}-\int 3 b (a+b \sin (c+d x))^2 \, dx \\ & = \frac {\sec (c+d x) (a+b \sin (c+d x))^3}{d}-(3 b) \int (a+b \sin (c+d x))^2 \, dx \\ & = -\frac {3}{2} b \left (2 a^2+b^2\right ) x+\frac {6 a b^2 \cos (c+d x)}{d}+\frac {3 b^3 \cos (c+d x) \sin (c+d x)}{2 d}+\frac {\sec (c+d x) (a+b \sin (c+d x))^3}{d} \\ \end{align*}
Time = 0.80 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.21 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=\frac {\sec (c+d x) \left (8 a^3+36 a b^2+12 a b^2 \cos (2 (c+d x))+b^3 \sin (3 (c+d x))\right )+3 b \left (-4 \left (2 a^2+b^2\right ) (c+d x)+\left (8 a^2+3 b^2\right ) \tan (c+d x)\right )}{8 d} \]
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Time = 0.69 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.43
method | result | size |
parallelrisch | \(\frac {12 a \,b^{2} \cos \left (2 d x +2 c \right )+b^{3} \sin \left (3 d x +3 c \right )+\left (-24 a^{2} b d x -12 b^{3} d x +8 a^{3}+48 a \,b^{2}\right ) \cos \left (d x +c \right )+\left (24 a^{2} b +9 b^{3}\right ) \sin \left (d x +c \right )+8 a^{3}+36 a \,b^{2}}{8 d \cos \left (d x +c \right )}\) | \(107\) |
derivativedivides | \(\frac {\frac {a^{3}}{\cos \left (d x +c \right )}+3 a^{2} b \left (\tan \left (d x +c \right )-d x -c \right )+3 a \,b^{2} \left (\frac {\sin ^{4}\left (d x +c \right )}{\cos \left (d x +c \right )}+\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )\right )+b^{3} \left (\frac {\sin ^{5}\left (d x +c \right )}{\cos \left (d x +c \right )}+\left (\sin ^{3}\left (d x +c \right )+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )}{d}\) | \(132\) |
default | \(\frac {\frac {a^{3}}{\cos \left (d x +c \right )}+3 a^{2} b \left (\tan \left (d x +c \right )-d x -c \right )+3 a \,b^{2} \left (\frac {\sin ^{4}\left (d x +c \right )}{\cos \left (d x +c \right )}+\left (2+\sin ^{2}\left (d x +c \right )\right ) \cos \left (d x +c \right )\right )+b^{3} \left (\frac {\sin ^{5}\left (d x +c \right )}{\cos \left (d x +c \right )}+\left (\sin ^{3}\left (d x +c \right )+\frac {3 \sin \left (d x +c \right )}{2}\right ) \cos \left (d x +c \right )-\frac {3 d x}{2}-\frac {3 c}{2}\right )}{d}\) | \(132\) |
risch | \(-3 a^{2} b x -\frac {3 b^{3} x}{2}-\frac {i b^{3} {\mathrm e}^{2 i \left (d x +c \right )}}{8 d}+\frac {3 \,{\mathrm e}^{i \left (d x +c \right )} a \,b^{2}}{2 d}+\frac {3 \,{\mathrm e}^{-i \left (d x +c \right )} a \,b^{2}}{2 d}+\frac {i b^{3} {\mathrm e}^{-2 i \left (d x +c \right )}}{8 d}+\frac {2 i \left (-i a^{3} {\mathrm e}^{i \left (d x +c \right )}-3 i a \,b^{2} {\mathrm e}^{i \left (d x +c \right )}+3 a^{2} b +b^{3}\right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}\) | \(147\) |
norman | \(\frac {-\frac {2 a^{3}+12 a \,b^{2}}{d}+\frac {3 b \left (2 a^{2}+b^{2}\right ) x}{2}-\frac {2 a^{3} \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {2 \left (3 a^{3}+12 a \,b^{2}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {6 a \left (a^{2}+2 b^{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {3 b \left (2 a^{2}+b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}-\frac {3 b \left (2 a^{2}+b^{2}\right ) \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+3 b \left (2 a^{2}+b^{2}\right ) x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-3 b \left (2 a^{2}+b^{2}\right ) x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {3 b \left (2 a^{2}+b^{2}\right ) x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}-\frac {b \left (18 a^{2}+5 b^{2}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {b \left (18 a^{2}+5 b^{2}\right ) \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{3} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}\) | \(314\) |
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Time = 0.28 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.20 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=\frac {6 \, a b^{2} \cos \left (d x + c\right )^{2} - 3 \, {\left (2 \, a^{2} b + b^{3}\right )} d x \cos \left (d x + c\right ) + 2 \, a^{3} + 6 \, a b^{2} + {\left (b^{3} \cos \left (d x + c\right )^{2} + 6 \, a^{2} b + 2 \, b^{3}\right )} \sin \left (d x + c\right )}{2 \, d \cos \left (d x + c\right )} \]
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\[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=\int \left (a + b \sin {\left (c + d x \right )}\right )^{3} \sin {\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}\, dx \]
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Time = 0.28 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.32 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=-\frac {6 \, {\left (d x + c - \tan \left (d x + c\right )\right )} a^{2} b + {\left (3 \, d x + 3 \, c - \frac {\tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2} + 1} - 2 \, \tan \left (d x + c\right )\right )} b^{3} - 6 \, a b^{2} {\left (\frac {1}{\cos \left (d x + c\right )} + \cos \left (d x + c\right )\right )} - \frac {2 \, a^{3}}{\cos \left (d x + c\right )}}{2 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 148 vs. \(2 (71) = 142\).
Time = 0.42 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.97 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=-\frac {3 \, {\left (2 \, a^{2} b + b^{3}\right )} {\left (d x + c\right )} + \frac {4 \, {\left (3 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a^{3} + 3 \, a b^{2}\right )}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1} + \frac {2 \, {\left (b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 6 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 6 \, a b^{2}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{2}}}{2 \, d} \]
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Time = 15.40 (sec) , antiderivative size = 219, normalized size of antiderivative = 2.92 \[ \int \sec (c+d x) (a+b \sin (c+d x))^3 \tan (c+d x) \, dx=\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (6\,a^2\,b+3\,b^3\right )+2\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+12\,a\,b^2+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (4\,a^3+12\,a\,b^2\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (6\,a^2\,b+3\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (12\,a^2\,b+2\,b^3\right )+2\,a^3}{d\,\left (-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}-\frac {3\,b\,\mathrm {atan}\left (\frac {3\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (2\,a^2+b^2\right )}{6\,a^2\,b+3\,b^3}\right )\,\left (2\,a^2+b^2\right )}{d} \]
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